3.125 \(\int x^2 (d+e x^2)^{3/2} (a+b \sec ^{-1}(c x)) \, dx\)

Optimal. Leaf size=25 \[ \text{Unintegrable}\left (x^2 \left (d+e x^2\right )^{3/2} \left (a+b \sec ^{-1}(c x)\right ),x\right ) \]

[Out]

Unintegrable[x^2*(d + e*x^2)^(3/2)*(a + b*ArcSec[c*x]), x]

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Rubi [A]  time = 0.112009, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int x^2 \left (d+e x^2\right )^{3/2} \left (a+b \sec ^{-1}(c x)\right ) \, dx \]

Verification is Not applicable to the result.

[In]

Int[x^2*(d + e*x^2)^(3/2)*(a + b*ArcSec[c*x]),x]

[Out]

Defer[Int][x^2*(d + e*x^2)^(3/2)*(a + b*ArcSec[c*x]), x]

Rubi steps

\begin{align*} \int x^2 \left (d+e x^2\right )^{3/2} \left (a+b \sec ^{-1}(c x)\right ) \, dx &=\int x^2 \left (d+e x^2\right )^{3/2} \left (a+b \sec ^{-1}(c x)\right ) \, dx\\ \end{align*}

Mathematica [A]  time = 8.75291, size = 0, normalized size = 0. \[ \int x^2 \left (d+e x^2\right )^{3/2} \left (a+b \sec ^{-1}(c x)\right ) \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[x^2*(d + e*x^2)^(3/2)*(a + b*ArcSec[c*x]),x]

[Out]

Integrate[x^2*(d + e*x^2)^(3/2)*(a + b*ArcSec[c*x]), x]

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Maple [A]  time = 1.458, size = 0, normalized size = 0. \begin{align*} \int{x}^{2} \left ( e{x}^{2}+d \right ) ^{{\frac{3}{2}}} \left ( a+b{\rm arcsec} \left (cx\right ) \right ) \, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(e*x^2+d)^(3/2)*(a+b*arcsec(c*x)),x)

[Out]

int(x^2*(e*x^2+d)^(3/2)*(a+b*arcsec(c*x)),x)

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(e*x^2+d)^(3/2)*(a+b*arcsec(c*x)),x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (a e x^{4} + a d x^{2} +{\left (b e x^{4} + b d x^{2}\right )} \operatorname{arcsec}\left (c x\right )\right )} \sqrt{e x^{2} + d}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(e*x^2+d)^(3/2)*(a+b*arcsec(c*x)),x, algorithm="fricas")

[Out]

integral((a*e*x^4 + a*d*x^2 + (b*e*x^4 + b*d*x^2)*arcsec(c*x))*sqrt(e*x^2 + d), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(e*x**2+d)**(3/2)*(a+b*asec(c*x)),x)

[Out]

Timed out

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Giac [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (e x^{2} + d\right )}^{\frac{3}{2}}{\left (b \operatorname{arcsec}\left (c x\right ) + a\right )} x^{2}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(e*x^2+d)^(3/2)*(a+b*arcsec(c*x)),x, algorithm="giac")

[Out]

integrate((e*x^2 + d)^(3/2)*(b*arcsec(c*x) + a)*x^2, x)